Answer
In probability theory, the expectation of a random variable is the weighted average of all possible values that this random variable can take on.
Thus, for one dice the expectation is
1/6*(1+2+3+4+5+6) = 3.5
and as the expectation of two indepentent distributions is the sum of the expectation of each, the answer would be
3.5+3.5 = 7
In probability theory, the expectation of a random variable is the weighted average of all possible values that this random variable can take on.
Thus, for one dice the expectation is
1/6*(1+2+3+4+5+6) = 3.5
and as the expectation of two indepentent distributions is the sum of the expectation of each, the answer would be
3.5+3.5 = 7