You are given a box 2 inches by 1000 inches in size, and an unlimited supply of coins. Each coin is exactly one inch in diameter.
How many coins can you place flat in the bottom of the box without overlapping?
Hint: answer is more than 2000
How many coins can you place flat in the bottom of the box without overlapping?
Hint: answer is more than 2000
So, the area of the coin is pi*R^2=0.785
Area of the box is 2000.
The ideal case of full filling ex. square coins: 2546 coins (never happends, but gives an upper limit).
According to Wikipedia good packaging have an average density of ~0.90, so 2000 x 0.90=1800 sq inches.
1800 / 0.785 = 2292.xxx
So, the answer should be 2292
http://en.wikipedia.org/wiki/Sphere_packing